# Module 6 Statistics Discussion Questions

## M.Triola, Elementary Statistics, 13th Edition,

page 372, ##20,24

page 383, #10

372 # 20, 24

20. P values.

A. ID the hypothesis test as being two tailed, left or right tailed

B. Find the P value

C. Using a significance level of a=.05 should we reject or fail to reject null

20. The test statistic of Z= -1.94 is obtained when testing the claim that p=3/8

H0: P=3/8 or .375

H1: P≠3/8 or .375

H1< left tail) H1> right tail) H1≠ two tailed

Normalcdf ( -99999, -1.94 = .0262

Two tails .0262*2

P-Value=.0524

.0524 > .05 SO fail to reject

24. Critical values

A. Find the critical values

B. LOS a=.05 should we reject or fail to reject null

24. Exercise 20

Critical region -1.94 from 20

T test

Divide .05 by 2=.025

Invonorm (.025= -1.96

1-.025=1.96

Fail to reject because -1.96 is not inside the critical region -1.94

383 #10 test the given claim. A. Identify the null hypothesis, alternative hypothesis, B. test statistic, P-value, or critical value(s), then C. state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section.

Eliquis: The drug Eliquis (apixaban) is used to help prevent blood clots in certain patients. In clinical trials, among 5924 patients treated with Eliquis, 153 developed the adverse reaction of nausea (based on data from Bristol Myers Squibb Co.). Use a .05 significance level to test the claim that 3% of Eliquis users develop nausea. Does nausea appear to be a problematic adverse reaction?

Claim: U=.03 n=5924 xbar= 153 a=.05

H0 p=.03 1 prop Ztest

H1 P≠.03 P=.0597> .05 So fail to reject

Conclusion is that the mean 3% of Eliquis users develop nausea

Last Updated on September 28, 2018 by EssayPro